数字大小写

小写转大写

        硬性拆分

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public  String digitUppercase(String num) throws Exception{  
        String fraction[] = {"角", "分"};  
        String digit[] = { "零", "壹", "贰", "叁", "肆", "伍", "陆", "柒", "捌", "玖" };
        String unit1[] = {"", "拾", "佰", "仟"};//把钱数分成段,每四个一段,实际上得到的是一个二维数组  
        String unit2[] = {"元", "万", "亿","万亿"}; //把钱数分成段,每四个一段,实际上得到的是一个二维数组  
        BigDecimal bigDecimal =  new BigDecimal(num);  
        bigDecimal=bigDecimal.multiply(new BigDecimal(100));  
        String strVal = String.valueOf(bigDecimal.toBigInteger());  
        if("0".equals(strVal)){
        	strVal = "000";
        }
        String head = strVal.substring(0,strVal.length()-2);         //整数部分  
        String end = strVal.substring(strVal.length()-2);              //小数部分  
        String endMoney="";  
        String headMoney = "";  
        if("00".equals(end)){  
            endMoney = "整";  
        }else{  
            if(!end.substring(0,1).equals("0")){  
                endMoney+=digit[Integer.valueOf(end.substring(0,1))]+"角";  
            }else if(end.substring(0,1).equals("0") && !end.substring(1,2).equals("0")){  
                endMoney+= "零";  
            }  
            if(!end.substring(1,2).equals("0")){  
                endMoney+=digit[Integer.valueOf(end.substring(1,2))]+"分";  
            }  
        }  
        char[] chars = head.toCharArray();  
        Map<String,Boolean> map = new HashMap<String,Boolean>();//段位置是否已出现zero  
        boolean zeroKeepFlag = false;//0连续出现标志  
        int vidxtemp = 0;  
        for(int i=0;i<chars.length;i++){  
            int idx = (chars.length-1-i)%4;//段内位置  unit1  
            int vidx = (chars.length-1-i)/4;//段位置 unit2  
            String s = digit[Integer.valueOf(String.valueOf(chars[i]))];  
            if(!"零".equals(s)){  
                headMoney += s +unit1[idx]+unit2[vidx];  
                zeroKeepFlag = false;  
            }else if(i==chars.length-1 || map.get("zero"+vidx)!=null){  
                headMoney += "" ;  
            }else{  
                headMoney += s;  
                zeroKeepFlag = true;  
                map.put("zero"+vidx,true);//该段位已经出现0；  
            }  
            if(vidxtemp!=vidx || i==chars.length-1){  
                headMoney = headMoney.replaceAll(unit2[vidx],"");  
                headMoney+=unit2[vidx];  
            }  
            if(zeroKeepFlag && (chars.length-1-i)%4==0){  
                headMoney = headMoney.replaceAll("零","");  
            }  
        }  
        
        return "元整".equals(headMoney+endMoney)?"零元整":headMoney+endMoney;  
    }